Half-life is the time it takes for half of a substance to decay or transform. It appears in nuclear physics, pharmacology, chemistry, and archaeology — wherever something decreases exponentially.
The Half-Life Formula
N(t) = N₀ × (½)^(t/t½)
Or equivalently:
N(t) = N₀ × e^(−λt)
Where:
- N(t) = remaining quantity at time t
- N₀ = initial quantity
- t½ = half-life period
- λ = decay constant = ln(2) ÷ t½ ≈ 0.693 ÷ t½
- e = Euler's number (2.718...)
Basic Half-Life Calculation
How much remains after n half-lives?
Remaining fraction = (½)^n = 1 ÷ 2^n
| Half-Lives Elapsed | Fraction Remaining | Percentage |
|---|---|---|
| 1 | 1/2 | 50% |
| 2 | 1/4 | 25% |
| 3 | 1/8 | 12.5% |
| 4 | 1/16 | 6.25% |
| 5 | 1/32 | 3.125% |
| 7 | 1/128 | 0.78% |
| 10 | 1/1024 | 0.098% |
Example: 200 g of a substance with a 10-day half-life, after 30 days:
- Number of half-lives = 30 ÷ 10 = 3
- Remaining = 200 × (½)³ = 200 × 0.125 = 25 g
Finding Remaining Amount at Any Time
N(t) = N₀ × (½)^(t/t½)
Example: 500 mg substance, half-life = 8 hours. How much remains after 20 hours?
- N(20) = 500 × (½)^(20/8)
- N(20) = 500 × (0.5)^2.5
- N(20) = 500 × 0.1768 = 88.4 mg
Finding Elapsed Time from Remaining Amount
t = t½ × log(N(t)/N₀) ÷ log(½)
Or: t = t½ × ln(N₀/N(t)) ÷ ln(2)
Example: Start with 1,000 g, half-life = 5 years. When does 62.5 g remain?
- 62.5/1,000 = 0.0625 = (½)^n → n = 4 half-lives
- t = 4 × 5 = 20 years
The Decay Constant
λ = ln(2) ÷ t½ ≈ 0.693 ÷ t½
The decay constant λ is the probability per unit time that a nucleus will decay. It's used in the exponential decay formula:
N(t) = N₀ × e^(−λt)
Example: Half-life = 20 minutes:
- λ = 0.693 ÷ 20 = 0.03466 per minute
- After 60 minutes: N = N₀ × e^(−0.03466 × 60) = N₀ × e^(−2.079) = N₀ × 0.125
This confirms: 60 minutes = 3 half-lives → 12.5% remaining ✓
Radioactive Isotope Half-Lives
| Isotope | Half-Life | Use |
|---|---|---|
| Carbon-14 | 5,730 years | Radiocarbon dating |
| Uranium-238 | 4.47 billion years | Geological age dating |
| Iodine-131 | 8.02 days | Thyroid cancer treatment |
| Technetium-99m | 6.01 hours | Medical imaging |
| Polonium-210 | 138.4 days | — |
| Strontium-90 | 28.8 years | Nuclear fallout concern |
Carbon Dating: Practical Application
Carbon-14 has a half-life of 5,730 years and is found in all living organisms. When an organism dies, it stops absorbing new C-14, so the ratio of C-14 to C-12 decreases predictably.
Age = t½ ÷ ln(2) × ln(N₀/N)
Example: A sample has 25% of its original C-14 remaining:
- 25% = (½)^n → n = 2 half-lives
- Age = 2 × 5,730 = 11,460 years old
Carbon dating is reliable for samples up to ~50,000 years old (approximately 8–9 half-lives, after which so little C-14 remains that measurement becomes unreliable).
Half-Life in Pharmacology
Drug half-life determines dosing frequency. After 4–5 half-lives, approximately 94–97% of a drug has been eliminated:
| Drug | Half-Life | Dosing Frequency |
|---|---|---|
| Ibuprofen | 2 hours | Every 4–6 hours |
| Aspirin | 15–20 minutes* | Daily for antiplatelet |
| Caffeine | 5–6 hours | Effects ~8–10 hours |
| Diazepam (Valium) | 20–100 hours | Once daily or less |
*Aspirin's effects on platelets last much longer than its own half-life due to irreversible binding.
Use our exponent calculator to compute (½)^n for any number of half-lives quickly.