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Calculates minimum PCB trace width for current capacity considering voltage drop and temperature rise. Prevents overheating and signal degradation.

Формула

Formula: width (mils) = current (A) ÷ (ampacity × thickness)
A
A value — Variable used in the calculation

Пошаговое руководство

  1. 1Current flowing through trace
  2. 2Trace length and thickness (oz/ft² of copper)
  3. 3Ampacity nomogram: 1 oz, 1 A/mil² roughly
  4. 4Formula: width (mils) = current (A) ÷ (ampacity × thickness)
  5. 5Account for temperature limits

Решённые примеры

Ввод
Current 2A, copper 1oz
Результат
Width 20 mil

Распространённые ошибки

  • Using minimum trace width to reduce design time
  • Not accounting for temperature derating in high-current boards

Часто задаваемые вопросы

Why does trace width matter?

Thin traces carry less current, overheat, and can catch fire; wide traces prevent damage.

What's voltage drop in traces?

50-100 mV acceptable for power; too much dropout regulator can't maintain voltage.

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